Difference between 2 12s and 1 15

what is the sound difference between 2 12s or 1 15
WE got too many immature members in this site, you might wanna be more specific with you'r question, unless you wanna go thru a couple of pages of pointless comments like the ones on top.

 
WE got too many immature members in this site, you might wanna be more specific with you'r question, unless you wanna go thru a couple of pages of pointless comments like the ones on top.
what do you mean the ones on top.....the first two are very true answers.....

 
all things equal 15=176.62 sq in vs 2 12s=226sq in as far as cone area goes so the 12 should move a bit more air . the 15 generally should be able to play a lower frequencies easier. anything outside of that ill come down to the drivers, install, etc as mentioned before

 
Actually the ability to play low frequencies is dependant on the ability to move air, therefore the 12s have the advantage. They will also be louder off the same power thnks to the increased cone area. In high power situations they will experience less power compression because of the two motor assemblies available ot shed heat. In SQ situations they will usually sound better becuase they require less excursion for a given output level and thus will suffer less from suspension and motor non-linearities that occur farther from the center posistion of the motor.

 
Say you have a total of 1500 watts. Would the 2 12's be louder of the 1 15" (given they are the same sub brand/model only difference in size)

The 2 12's would each get 750 watts. So 750 watts to ~ 226 ft^2.

The 1 15 would get 1500 watts. So 1500 watts to ~ 176.62ft^2.

The 12's have a cone area advantage but the 15 has a power advantage. Shouldn't it be very close in output? Or am i not thinking about this right?

 
Say you have a total of 1500 watts. Would the 2 12's be louder of the 1 15" (given they are the same sub brand/model only difference in size)
The 2 12's would each get 750 watts. So 750 watts to ~ 226 ft^2.

The 1 15 would get 1500 watts. So 1500 watts to ~ 176.62ft^2.

The 12's have a cone area advantage but the 15 has a power advantage. Shouldn't it be very close in output? Or am i not thinking about this right?
The 15 in this scenario does not have ANY power advantage. You still have a total of 1500W going to the 12's -- so the power is the same, but the 12's have the cone area advantage... and they are not suffering from as much power compression as the 15".
This would give the 12's a slight advantage...

 
The 15 in this scenario does not have ANY power advantage. You still have a total of 1500W going to the 12's -- so the power is the same, but the 12's have the cone area advantage... and they are not suffering from as much power compression as the 15".
This would give the 12's a slight advantage...
So you have 2 12's subs

750 watts to a 12"(113 ft^2)

750 watts to the other (113ft^2)

when you add them together you add the power and the cone area? I'm just a little confused as to why that is. When more power is added the cone will have a higher excursion, right? So say the sub we are talking about moves out 1 inch when given 750 watts. It should not matter what size the sub is, they all have the same excursion limitations. So with 2 12's (each getting 750w) their is a total of 226^2 moving out 1 inch, correct? Now say their is a sub size that is equal to 226^2 (17 inch sub?). This 17" sub is fed 750 watts, so it should also have an excursion of 1 inch.

With the 2 12's, a total of 226^2 is moving 1 inch

With the 1 17", a total of 226^2 is moving 1 inch

shouldn't they be equal in output? I'm still kind of confused on why when you have multiple subs you increase both power and area. if you add both power and area the 226^2 from the 12's is getting 1500watts and the 226^2 from the 17" is getting 750watts, which doesn't make since to me if the same amount of cone area is moving the same distance.

 
So what about 2 15's versus 3 12's? Assuming the same scenario as before (same model subs being compared) would the 12's still hold the advantage?

 
So you have 2 12's subs 750 watts to a 12"(113 ft^2)

750 watts to the other (113ft^2)

when you add them together you add the power and the cone area? I'm just a little confused as to why that is. When more power is added the cone will have a higher excursion, right? So say the sub we are talking about moves out 1 inch when given 750 watts. It should not matter what size the sub is, they all have the same excursion limitations. So with 2 12's (each getting 750w) their is a total of 226^2 moving out 1 inch, correct? Now say their is a sub size that is equal to 226^2 (17 inch sub?). This 17" sub is fed 750 watts, so it should also have an excursion of 1 inch.

With the 2 12's, a total of 226^2 is moving 1 inch

With the 1 17", a total of 226^2 is moving 1 inch

shouldn't they be equal in output? I'm still kind of confused on why when you have multiple subs you increase both power and area. if you add both power and area the 226^2 from the 12's is getting 1500watts and the 226^2 from the 17" is getting 750watts, which doesn't make since to me if the same amount of cone area is moving the same distance.
The flaw in your logic is assuming that the 17" sub with at least twice the moving mass of one of the 12s will move as far with 750w as one of the 12s would. The fact is that it wouldn't assuming the same motor force (same motor). It would move half as far and thus have half the swept volume for a theoretical decrease of 3dB in output in a sealed enclosure. You'd have to through 1500w at the big sub to get it to move as far as one of the 12s with 750.

 
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